Assuming the parts are separated with a space, and you want to extract the RANDOM parts only:
var randoms = json
.replace(/\b(one|two|three|four|five|six|seven|eight|nine)\b\s*/gi, '')
.match(/\S+/g);
Since JS doesn't have negative look-ahead, we strip the recognized words first (globally i.e. all occurrences, case-insensitively), then all that's left is the random words which we extract using the non-whitespace token \S+.
I want to remove all RANDOM
But RANDOM is unknown word it's random word
json = one two RANDOM four
If (json.match(one|two|three|four) --> false
json = one two three four
If (json.match(one|two|three|four) --> true
Working like this http://www.regextester.com/15 but this RegEx not work with "one two RANDOM four"
Ah! Then you need to strip all known words and see if the result is empty because JS regexp doesn't have negative look-ahead:
var hasRandom = json
.replace(/\s*(one|two|three|four|five|six|seven|eight|nine)\s*/gi, '').trim();
if (!hasRandom) {
}
Okay now it's work thanks alot
How to match string is not match
json = one two RANDOM three four five RANDOM six seven eight RANDOM nine zero
if found any word other than "one two three four five six seven eight nine zero" How i can match RANDOM string ?
if(json.match('one|two|three|four|five|six|seven|eight|nine|zero|One|Two|Three|Four|Five|Six|Seven|Eight|Nine|Zero')){
}else{
}