debug

用于调试的脚本库

Від 16.11.2017. Дивіться остання версія.

Цей скрипт не слід встановлювати безпосередньо. Це - бібліотека для інших скриптів для включення в мета директиву // @require https://update.greasyfork.org/scripts/34143/230828/debug.js

You will need to install an extension such as Tampermonkey, Greasemonkey or Violentmonkey to install this script.

You will need to install an extension such as Tampermonkey to install this script.

You will need to install an extension such as Tampermonkey or Violentmonkey to install this script.

You will need to install an extension such as Tampermonkey or Userscripts to install this script.

You will need to install an extension such as Tampermonkey to install this script.

You will need to install a user script manager extension to install this script.

(У мене вже є менеджер скриптів, дайте мені встановити його!)

You will need to install an extension such as Stylus to install this style.

You will need to install an extension such as Stylus to install this style.

You will need to install an extension such as Stylus to install this style.

You will need to install a user style manager extension to install this style.

You will need to install a user style manager extension to install this style.

You will need to install a user style manager extension to install this style.

(I already have a user style manager, let me install it!)

// ==UserScript==
// @name         debug
// @namespace    https://github.com/yeomanye
// @version      0.5.1
// @include      *://*
// @description  用于调试的脚本库
// @author       Ming Ye
// ==/UserScript==

// 开启调试
var consoleFactory = function(prefix, type,suffix,debugMode) {
    prefix = prefix || "";
    type = type || "log";
    suffix = suffix || "";
    return function(msg){
        if (debugMode) {
            var arguments = Array.prototype.slice.apply(arguments);
            arguments.unshift(prefix);
            arguments.push(suffix);
            console[type].apply(null,arguments);
        }
    };
};

// 当参数为true时开启调试
var debugTrue = function(isDebugger){
    if(isDebugger) debugger;
}