This script makes it so you can navigate marketplace with arrow keys between next and previous pages. It also attemps to remove duplicates from results(highly imperfect).
Versión del día
// ==UserScript==
// @name Arrow Keys navigate Marketplace
// @namespace http://tampermonkey.net/
// @version 0.4
// @license MIT
// @description This script makes it so you can navigate marketplace with arrow keys between next and previous pages. It also attemps to remove duplicates from results(highly imperfect).
// @author Aida Beorn
// @match https://marketplace.secondlife.com/*
// @icon https://www.google.com/s2/favicons?domain=secondlife.com
// @grant None
// ==/UserScript==
function NextPage() {
let next = document.getElementsByClassName('next_page')[0];
if(next) {
next.click();
}
}
function PreviousPage() {
let prev = document.getElementsByClassName('previous_page')[0];
if(prev) {
prev.click();
}
}
function HandleKeyEvent(e) {
switch(e.key) {
case "ArrowRight":
NextPage();
break;
case "ArrowLeft":
PreviousPage();
break;
}
}
(function() {
'use strict';
document.addEventListener('keydown', HandleKeyEvent);
RemoveDuplicates();
})();
function RemoveDuplicates() {
let items1 = document.getElementsByClassName('gallery-item');
let items2 = document.getElementsByClassName('gallery-item');
let count = 0;
for(let i = 0; i < items1.length; i++) {
for(let k = 0; k < items2.length; k++) {
const a = items1[i];
const b = items2[k];
const levDistance = levenshteinDistance(a.children[1].innerText, b.children[1].innerText);
if(levDistance < 7 && i !== k) {
//console.log(`${a.children[1].innerText}::${b.children[1].innerText}::${levDistance}`);
b.remove();
count++;
}
}
}
console.log(`Removed ${count} items`);
}
function levenshteinDistance(a, b){
if(a.length == 0) return b.length;
if(b.length == 0) return a.length;
var matrix = [];
// increment along the first column of each row
var i;
for(i = 0; i <= b.length; i++){
matrix[i] = [i];
}
// increment each column in the first row
var j;
for(j = 0; j <= a.length; j++){
matrix[0][j] = j;
}
// Fill in the rest of the matrix
for(i = 1; i <= b.length; i++){
for(j = 1; j <= a.length; j++){
if(b.charAt(i-1) == a.charAt(j-1)){
matrix[i][j] = matrix[i-1][j-1];
} else {
matrix[i][j] = Math.min(matrix[i-1][j-1] + 1, // substitution
Math.min(matrix[i][j-1] + 1, // insertion
matrix[i-1][j] + 1)); // deletion
}
}
}
return matrix[b.length][a.length];
};